Розрахунок: 3yZMaj - 1

B =

μ* μ0* I

/ ( 2* π

* r)

B =

μ* μ0* I

/ ( 2* π

* r)

$B$ = $\frac{\mu\cdot \mu0\cdot I}{2\cdot \pi\cdot r}$

μ* μ0* I

/ ( 2* π

* r)

= B $\frac{\mu\cdot \mu0\cdot I}{2\cdot \pi\cdot r}$ = $B$

μ* μ0* I

/ 2/ π

/ r

= B $\frac{\mu\cdot \mu0\cdot I}{2\cdot \pi\cdot r}$ = $B$

μ* μ0* I = 2* B* π

* r $\mu\cdot \mu0\cdot I$ = $2\cdot B\cdot \pi\cdot r$

I =

2* B* π

* r

/ μ/ μ0

$I$ = $\frac{2\cdot B\cdot \pi\cdot r}{\mu\cdot \mu0}$

I =

2* B* r* π

/ μ/ μ0

$I$ = $\frac{2\cdot B\cdot r\cdot \pi}{\mu\cdot \mu0}$