Розрахунок: LNgcbk - 1

B  = 
 
 μ* μ0* I* (cos(a1)+cos(a2))
/ ( 4* π* r)
B =  
 μ* μ0* I* (cos(a1)+cos(a2))
/ ( 4* π* r)
$$B$$ = $$\frac{\mu\cdot \mu0\cdot I\cdot (cos(a1)+cos(a2))}{4\cdot \pi\cdot r}$$
B =  
 I* cos( 
 (a1+a2)
/ 2
)
* cos( 
 (a1-a2)
/ 2
)
* μ* μ0
/ 2/ r/ π
$$B$$ = $$\frac{I\cdot cos(\frac{a1+a2}{2})\cdot cos(\frac{a1-a2}{2})\cdot \mu\cdot \mu0}{2\cdot r\cdot \pi}$$
B =  
 0.5* I* cos( 0.5* (a1+a2))* cos( 0.5* (a1-a2))* μ* μ0
/ r/ π
$$B$$ = $$\frac{0.5\cdot I\cdot cos(0.5\cdot (a1+a2))\cdot cos(0.5\cdot (a1-a2))\cdot \mu\cdot \mu0}{r\cdot \pi}$$